{"id":13188,"date":"2024-10-11T10:19:25","date_gmt":"2024-10-11T08:19:25","guid":{"rendered":"https:\/\/calcul-electrique.com\/non-classifiee\/too-much-thermal-stress-on-the-phase-conductor\/"},"modified":"2024-12-31T11:42:05","modified_gmt":"2024-12-31T10:42:05","slug":"too-much-thermal-stress-on-the-phase-conductor","status":"publish","type":"post","link":"https:\/\/calcul-electrique.com\/en\/faq-elec-calc-en\/calculation\/too-much-thermal-stress-on-the-phase-conductor\/","title":{"rendered":"Too much thermal stress on the phase conductor"},"content":{"rendered":"\n<div class=\"wp-block-uagb-container uagb-block-36487dc3 alignfull uagb-is-root-container\"><div class=\"uagb-container-inner-blocks-wrap\">\n<div class=\"wp-block-uagb-container uagb-block-fd17fc7a\">\n<div class=\"wp-block-uagb-container uagb-block-9d42b2c7\">\n<div class=\"wp-block-uagb-advanced-heading uagb-block-e514becd\"><h5 class=\"uagb-heading-text\">Article 434.5.2 of standard NF C 15-100 :<\/h5><\/div>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">The breaking time of any current resulting from a short-circuit at any point in the circuit must not exceed the time required to bring the conductor temperature up to the permissible limit.  <\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">For short-circuits lasting up to 5 s, the time required for a short-circuit current to raise the conductor temperature from the maximum permissible temperature in normal operation to the limit value can be calculated as a first approximation using the following formula :  <\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-ee321cc1\">\n<div class=\"wp-block-uagb-image uagb-block-9f9d3674 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-none\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Formule.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Formule.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Formule.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Formule.png\" alt=\"\" class=\"uag-image-4715\" width=\"208\" height=\"55\" title=\"Formule\" loading=\"lazy\" role=\"img\"\/><\/figure><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-6900450d\">\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Where:  <\/p>\n\n\n\n<div class=\"wp-block-uagb-icon-list uagb-block-d5207f78\"><div class=\"uagb-icon-list__wrap\">\n<div class=\"wp-block-uagb-icon-list-child uagb-block-dfe13fbc nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>t<\/strong> est la dur\u00e9e en secondes<\/span><\/div>\n\n\n\n<div class=\"wp-block-uagb-icon-list-child uagb-block-1b3e47de nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>S<\/strong> est la section en mm\u00b2<\/span><\/div>\n\n\n\n<div class=\"wp-block-uagb-icon-list-child uagb-block-de63382c nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>I<\/strong> est le courant de court-circuit effectif en A, exprim\u00e9 en valeur efficace (appel\u00e9<strong> I<sub>k<\/sub> <\/strong>dans le guide UTE C 15-105) <\/span><\/div>\n\n\n\n<div class=\"wp-block-uagb-icon-list-child uagb-block-32f07e74 nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>k<\/strong> = facteur tenant compte de la r\u00e9sistivit\u00e9, du coefficient de temp\u00e9rature et de la tenue d&#8217;\u00e9chauffements du mat\u00e9riau du conducteur, ainsi que des temp\u00e9ratures initiales finales. Pour les isolations les plus communes des conducteurs, les valeurs de <strong>k<\/strong> pour les conducteurs de phase sont indiqu\u00e9es dans le <strong>tableau 43A <\/strong>ci-dessous :<\/span><\/div>\n<\/div><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-305e6433\">\n<div class=\"wp-block-uagb-image uagb-block-856d5001 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-none\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/10\/43A.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/10\/43A.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/10\/43A.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/10\/43A.png\" alt=\"\" class=\"uag-image-4768\" width=\"1164\" height=\"393\" title=\"43A\" loading=\"lazy\" role=\"img\"\/><\/figure><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-e1977720\">\n<div class=\"wp-block-uagb-image aligncenter uagb-block-ec87960b wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-center\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Notes.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Notes.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Notes.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Notes.png\" alt=\"\" class=\"uag-image-4735\" width=\"1164\" height=\"255\" title=\"Notes\" loading=\"lazy\" role=\"img\"\/><\/figure><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-53189495\">\n<div class=\"wp-block-uagb-advanced-heading uagb-block-8fc1ba9d\"><h5 class=\"uagb-heading-text\">In elec calc\u2122 :<\/h5><\/div>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">The permissible thermal stress of a cable is its capacity to withstand a circuit current during its elimination time without the insulation being damaged.<\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">The value of the thermal stress is expressed in A\u00b2.s (I\u00b2t).<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-3f55f6ae\">\n<div class=\"wp-block-uagb-image aligncenter uagb-block-73e6c868 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-center\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-1.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-1.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-1.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-1.png\" alt=\"\" class=\"uag-image-4740\" width=\"690\" height=\"193\" title=\"Image 1\" loading=\"lazy\" role=\"img\"\/><\/figure><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-5c539d19\">\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">In the absence of a manufacturer&#8217;s reference upstream of the conductor, the thermal stress on the conductor is calculated as a function of the maximum short-circuit current seen by the cable and the circuit-breaker opening time: I\u00b2 x t (I in A and t in s).<\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">This value must be less than the thermal resistance of the cable: k\u00b2xS\u00b2.<\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Where:  <\/p>\n\n\n\n<div class=\"wp-block-uagb-icon-list uagb-block-7676eedd\"><div class=\"uagb-icon-list__wrap\">\n<div class=\"wp-block-uagb-icon-list-child uagb-block-8d96cb3e nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>S<\/strong> est la section du conducteur en mm\u00b2<\/span><\/div>\n\n\n\n<div class=\"wp-block-uagb-icon-list-child uagb-block-d707c2cb nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>k<\/strong> est un coefficient calcul\u00e9 suivant l&#8217;annexe B de la norme NF C 15-500 et donn\u00e9e \u00e9galement par les diff\u00e9rents tableaux de la m\u00eame annexe B.<\/span><\/div>\n<\/div><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-8ef24d09\">\n<div class=\"wp-block-uagb-advanced-heading uagb-block-ada632fe\"><h5 class=\"uagb-heading-text\">What&#8217;s the solution? Integrate a manufacturer reference on the upstream circuit breaker: <\/h5><\/div>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">To avoid oversizing the cable cross-section, manufacturers incorporate a limiting effect in most protections.  <\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Limitation is read directly from a manufacturer&#8217;s curve for upstream protection (circuit-breaker or fuse): <strong>the energy limitation curve<\/strong>. It defines the maximum thermal stress borne by the conductor, according to the maximum short-circuit current flowing through the pipe. <\/p>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-731290fd\">\n<div class=\"wp-block-uagb-image aligncenter uagb-block-d2db6174 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-center\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Courbes-1.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Courbes-1.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Courbes-1.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Courbes-1.png\" alt=\"\" class=\"uag-image-4758\" width=\"707\" height=\"326\" title=\"Courbes\" loading=\"lazy\" role=\"img\"\/><\/figure><\/div>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-eba35bed\">\n<div class=\"wp-block-uagb-advanced-heading uagb-block-9fc2743e\"><h5 class=\"uagb-heading-text\">Interpretation of thermal stress values in elec calc\u2122 :  <\/h5><\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-3c2a5e2f\">\n<div class=\"wp-block-uagb-image aligncenter uagb-block-d57ad3c7 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-center\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-last.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-last.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-last.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-last.png\" alt=\"\" class=\"uag-image-4750\" width=\"1164\" height=\"253\" title=\"Image last\" loading=\"lazy\" role=\"img\"\/><\/figure><\/div>\n<\/div>\n\n\n\n<p class=\"nc-justify-text has-black-color has-text-color has-link-color wp-elements-494991b5145d901f074458d8740fcf96\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">If <strong>i\u00b2t &gt; k\u00b2s\u00b2<\/strong>, a thermal stress anomaly appears on the cable.  <\/p>\n\n\n\n<p class=\"nc-justify-text has-black-color has-text-color has-link-color wp-elements-a023be227c2e938325a78aed2e040f9d\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">For more information, see this article on <a href=\"https:\/\/calcul-electrique.com\/articles\/technique\/la-verification-des-contraintes-thermiques-dans-un-conducteur\/\">checking thermal stresses in a conductor<\/a>.<\/p>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-0b867a31\">\n<p style=\"margin-top:0;margin-bottom:0\">You can also find the tutorial on thermal constraints below:<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-43bcf400\">\n<figure class=\"wp-block-embed aligncenter is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Tutoriel de formation elec calc\u2122 : La gestion des contraintes Thermiques\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/VN7-dLoK_x0?start=1&#038;feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n<\/div>\n<\/div><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Article 434.5.2 of standard NF C 15-100 : The breaking time of any current resulting from a short-circuit at any point in the circuit must not exceed the time required to bring the conductor temperature up to the permissible limit. For short-circuits lasting up to 5 s, the time required for a short-circuit current to [&hellip;]<\/p>\n","protected":false},"author":13,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"wp-custom-template-publications-2","format":"standard","meta":{"_uag_custom_page_level_css":"","_swt_meta_header_display":false,"_swt_meta_footer_display":false,"_swt_meta_site_title_display":false,"_swt_meta_sticky_header":false,"_swt_meta_transparent_header":false,"footnotes":""},"categories":[205,204],"tags":[],"class_list":["post-13188","post","type-post","status-publish","format-standard","hentry","category-calculation","category-faq-elec-calc-en"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.0 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Too much thermal stress on the phase conductor - Calcul \u00e9lectrique<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/calcul-electrique.com\/en\/faq-elec-calc-en\/too-much-thermal-stress-on-the-phase-conductor\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Too much thermal stress on the phase conductor - Calcul \u00e9lectrique\" \/>\n<meta property=\"og:description\" content=\"Article 434.5.2 of standard NF C 15-100 : The breaking time of any current resulting from a short-circuit at any point in the circuit must not exceed the time required to bring the conductor temperature up to the permissible limit. 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