{"id":13185,"date":"2024-10-11T10:19:25","date_gmt":"2024-10-11T08:19:25","guid":{"rendered":"https:\/\/calcul-electrique.com\/unkategorisiert\/zu-hohe-thermische-belastung-des-phasenleiters\/"},"modified":"2024-12-23T14:28:25","modified_gmt":"2024-12-23T13:28:25","slug":"zu-hohe-thermische-belastung-des-phasenleiters","status":"publish","type":"post","link":"https:\/\/calcul-electrique.com\/de\/faq-elec-calc-de\/zu-hohe-thermische-belastung-des-phasenleiters\/","title":{"rendered":"Zu hohe thermische Belastung des Phasenleiters"},"content":{"rendered":"\n<div class=\"wp-block-uagb-container uagb-block-36487dc3 alignfull uagb-is-root-container\"><div class=\"uagb-container-inner-blocks-wrap\">\n<div class=\"wp-block-uagb-container uagb-block-fd17fc7a\">\n<div class=\"wp-block-uagb-container uagb-block-9d42b2c7\">\n<div class=\"wp-block-uagb-advanced-heading uagb-block-e514becd\"><h5 class=\"uagb-heading-text\">Artikel Nr. 434.5.2 der Norm NF C 15-100:<\/h5><\/div>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Die Zeit, in der ein Kurzschluss an einer beliebigen Stelle des Stromkreises einen Strom unterbricht, darf nicht l\u00e4nger sein als die Zeit, in der die Temperatur der Leiter auf den zul\u00e4ssigen Grenzwert absinkt.  <\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Bei Kurzschl\u00fcssen mit einer Dauer von h\u00f6chstens 5 s kann die Zeit, die ein Kurzschlussstrom ben\u00f6tigt, um die Temperatur der Leiter von der h\u00f6chstzul\u00e4ssigen Temperatur im Normalbetrieb auf den Grenzwert zu erh\u00f6hen, in erster N\u00e4herung mit Hilfe der folgenden Formel berechnet werden:  <\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-ee321cc1\">\n<div class=\"wp-block-uagb-image uagb-block-9f9d3674 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-none\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Formule.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Formule.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Formule.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Formule.png\" alt=\"\" class=\"uag-image-4715\" width=\"208\" height=\"55\" title=\"Formel\" loading=\"lazy\" role=\"img\"><\/figure><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-6900450d\">\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Wo :  <\/p>\n\n\n\n<div class=\"wp-block-uagb-icon-list uagb-block-d5207f78\"><div class=\"uagb-icon-list__wrap\">\n<div class=\"wp-block-uagb-icon-list-child uagb-block-dfe13fbc nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewbox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>t<\/strong> ist die Dauer in Sekunden<\/span><\/div>\n\n\n\n<div class=\"wp-block-uagb-icon-list-child uagb-block-1b3e47de nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewbox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>S<\/strong> ist der Querschnitt in mm\u00b2.<\/span><\/div>\n\n\n\n<div class=\"wp-block-uagb-icon-list-child uagb-block-de63382c nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewbox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>I<\/strong> ist der effektive Kurzschlussstrom in A, ausgedr\u00fcckt als Effektivwert (<strong> in <\/strong>UTE C 15-105 als<strong> <sub>Ik<\/sub> <\/strong>bezeichnet).  <\/span><\/div>\n\n\n\n<div class=\"wp-block-uagb-icon-list-child uagb-block-32f07e74 nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewbox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>k<\/strong> = Faktor, der den spezifischen Widerstand, den Temperaturkoeffizienten und das Erw\u00e4rmungsverhalten des Leitermaterials sowie die anf\u00e4nglichen Endtemperaturen ber\u00fccksichtigt. F\u00fcr die gebr\u00e4uchlichsten Leiterisolierungen sind die Werte f\u00fcr <strong>k<\/strong> f\u00fcr Phasenleiter in <strong>Tabelle 43A <\/strong>unten aufgef\u00fchrt: <\/span><\/div>\n<\/div><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-305e6433\">\n<div class=\"wp-block-uagb-image uagb-block-856d5001 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-none\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/10\/43A.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/10\/43A.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/10\/43A.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/10\/43A.png\" alt=\"\" class=\"uag-image-4768\" width=\"1164\" height=\"393\" title=\"43A\" loading=\"lazy\" role=\"img\"><\/figure><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-e1977720\">\n<div class=\"wp-block-uagb-image aligncenter uagb-block-ec87960b wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-center\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Notes.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Notes.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Notes.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Notes.png\" alt=\"\" class=\"uag-image-4735\" width=\"1164\" height=\"255\" title=\"Anmerkungen\" loading=\"lazy\" role=\"img\"><\/figure><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-53189495\">\n<div class=\"wp-block-uagb-advanced-heading uagb-block-8fc1ba9d\"><h5 class=\"uagb-heading-text\">In elec calc\u2122 :<\/h5><\/div>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Die zul\u00e4ssige thermische Belastung eines Kabels ist seine F\u00e4higkeit, einen Strom des Schaltkreisstroms w\u00e4hrend seiner Eliminierungszeit zu ertragen, ohne dass die Isolierung besch\u00e4digt wird.<\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Der Wert der thermischen Spannung wird in A\u00b2.s (I\u00b2t) ausgedr\u00fcckt.<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-3f55f6ae\">\n<div class=\"wp-block-uagb-image aligncenter uagb-block-73e6c868 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-center\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-1.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-1.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-1.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-1.png\" alt=\"\" class=\"uag-image-4740\" width=\"690\" height=\"193\" title=\"Bild 1\" loading=\"lazy\" role=\"img\"><\/figure><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-5c539d19\">\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Da es keine Herstellerreferenz vor dem Leiter gibt, wird die thermische Belastung des Leiters als Funktion des maximalen Kurzschlussstroms, den das Kabel sieht, und der Ausschaltzeit des Schutzschalters berechnet: I\u00b2 x t (I in A und t in s).<\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Dieser Wert muss kleiner sein als die thermische Belastbarkeit des Kabels: k\u00b2xS\u00b2.<\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Wo :  <\/p>\n\n\n\n<div class=\"wp-block-uagb-icon-list uagb-block-7676eedd\"><div class=\"uagb-icon-list__wrap\">\n<div class=\"wp-block-uagb-icon-list-child uagb-block-8d96cb3e nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewbox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>S<\/strong> ist der Querschnitt des Leiters in mm\u00b2.<\/span><\/div>\n\n\n\n<div class=\"wp-block-uagb-icon-list-child uagb-block-d707c2cb nc-justify-text\"><span class=\"uagb-icon-list__source-wrap\"><svg xmlns=\"https:\/\/www.w3.org\/2000\/svg\" viewbox=\"0 0 256 512\"><path d=\"M64 448c-8.188 0-16.38-3.125-22.62-9.375c-12.5-12.5-12.5-32.75 0-45.25L178.8 256L41.38 118.6c-12.5-12.5-12.5-32.75 0-45.25s32.75-12.5 45.25 0l160 160c12.5 12.5 12.5 32.75 0 45.25l-160 160C80.38 444.9 72.19 448 64 448z\"><\/path><\/svg><\/span><span class=\"uagb-icon-list__label\"><strong>k<\/strong> ist ein Koeffizient, der gem\u00e4\u00df Anhang B der Norm NF C 15-500 berechnet wird und auch in den verschiedenen Tabellen desselben Anhangs B angegeben ist.<\/span><\/div>\n<\/div><\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-8ef24d09\">\n<div class=\"wp-block-uagb-advanced-heading uagb-block-ada632fe\"><h5 class=\"uagb-heading-text\">Was ist die L\u00f6sung? Integrieren Sie eine Herstellernummer auf dem vorgeschalteten Schutzschalter: <\/h5><\/div>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Um eine \u00dcberdimensionierung des Kabelquerschnitts zu vermeiden, bauen die Hersteller in die meisten Schutzvorrichtungen einen Begrenzereffekt ein.  <\/p>\n\n\n\n<p class=\"nc-justify-text\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Die Begrenzung wird direkt auf einer Herstellerkurve des vorgeschalteten Schutzes (Leistungsschalter oder Sicherung) abgelesen: <strong>die Energiebegrenzungskurve<\/strong>. Die Begrenzungslinie definiert die maximale thermische Belastung, der der Leiter ausgesetzt ist, abh\u00e4ngig vom maximalen Kurzschlussstrom, der durch die Leitung flie\u00dft. <\/p>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-731290fd\">\n<div class=\"wp-block-uagb-image aligncenter uagb-block-d2db6174 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-center\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Courbes-1.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Courbes-1.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Courbes-1.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Courbes-1.png\" alt=\"\" class=\"uag-image-4758\" width=\"707\" height=\"326\" title=\"Kurven\" loading=\"lazy\" role=\"img\"><\/figure><\/div>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-eba35bed\">\n<div class=\"wp-block-uagb-advanced-heading uagb-block-9fc2743e\"><h5 class=\"uagb-heading-text\">Interpretation der Werte der thermischen Spannung in elec calc\u2122 :  <\/h5><\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-3c2a5e2f\">\n<div class=\"wp-block-uagb-image aligncenter uagb-block-d57ad3c7 wp-block-uagb-image--layout-default wp-block-uagb-image--effect-static wp-block-uagb-image--align-center\"><figure class=\"wp-block-uagb-image__figure\"><img decoding=\"async\" srcset=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-last.png ,https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-last.png 780w, https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-last.png 360w\" sizes=\"auto, (max-width: 480px) 150px\" src=\"https:\/\/calcul-electrique.com\/wp-content\/uploads\/2024\/01\/Image-last.png\" alt=\"\" class=\"uag-image-4750\" width=\"1164\" height=\"253\" title=\"Letztes Bild\" loading=\"lazy\" role=\"img\"><\/figure><\/div>\n<\/div>\n\n\n\n<p class=\"nc-justify-text has-black-color has-text-color has-link-color wp-elements-6e8675695a9748635712290733bf97d1\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Wenn <strong>i\u00b2t &gt; k\u00b2s\u00b2<\/strong>, tritt eine thermische Spannungsanomalie auf dem Kabel auf.  <\/p>\n\n\n\n<p class=\"nc-justify-text has-black-color has-text-color has-link-color wp-elements-d3a756e0ed44a254b13e966ea29c15be\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0;padding-top:0;padding-right:0;padding-bottom:0;padding-left:0\">Wenn Sie weitere Informationen w\u00fcnschen, finden Sie hier einen Artikel \u00fcber die <a href=\"https:\/\/calcul-electrique.com\/articles\/technique\/la-verification-des-contraintes-thermiques-dans-un-conducteur\/\">\u00dcberpr\u00fcfung der thermischen Belastung in einem Leiter.<\/a><\/p>\n<\/div>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-0b867a31\">\n<p style=\"margin-top:0;margin-bottom:0\">Sie k\u00f6nnen auch das Tutorial zu thermischen Belastungen weiter unten finden:<\/p>\n<\/div>\n\n\n\n<div class=\"wp-block-uagb-container uagb-block-43bcf400\">\n<figure class=\"wp-block-embed aligncenter is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\" style=\"margin-top:0;margin-right:0;margin-bottom:0;margin-left:0\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Tutoriel de formation elec calc\u2122 : La gestion des contraintes Thermiques\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/VN7-dLoK_x0?start=1&#038;feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n<\/div>\n<\/div><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Artikel Nr. 434.5.2 der Norm NF C 15-100: Die Zeit, in der ein Kurzschluss an einer beliebigen Stelle des Stromkreises einen Strom unterbricht, darf nicht l\u00e4nger sein als die Zeit, in der die Temperatur der Leiter auf den zul\u00e4ssigen Grenzwert absinkt. Bei Kurzschl\u00fcssen mit einer Dauer von h\u00f6chstens 5 s kann die Zeit, die ein [&hellip;]<\/p>\n","protected":false},"author":13,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"wp-custom-template-publications-2","format":"standard","meta":{"_uag_custom_page_level_css":"","_swt_meta_header_display":false,"_swt_meta_footer_display":false,"_swt_meta_site_title_display":false,"_swt_meta_sticky_header":false,"_swt_meta_transparent_header":false,"footnotes":""},"categories":[203,202],"tags":[],"class_list":["post-13185","post","type-post","status-publish","format-standard","hentry","category-berechnung","category-faq-elec-calc-de"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.0 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Zu hohe thermische Belastung des Phasenleiters - Calcul \u00e9lectrique<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/calcul-electrique.com\/de\/faq-elec-calc-de\/zu-hohe-thermische-belastung-des-phasenleiters\/\" \/>\n<meta property=\"og:locale\" content=\"de_DE\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Zu hohe thermische Belastung des Phasenleiters - Calcul \u00e9lectrique\" \/>\n<meta property=\"og:description\" content=\"Artikel Nr. 434.5.2 der Norm NF C 15-100: Die Zeit, in der ein Kurzschluss an einer beliebigen Stelle des Stromkreises einen Strom unterbricht, darf nicht l\u00e4nger sein als die Zeit, in der die Temperatur der Leiter auf den zul\u00e4ssigen Grenzwert absinkt. 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